A bottling machine fills soda bottles with an average of 12.000 ounces of soda. The standard deviation is 0.002 ounces. If the design specification for the fill weight of the bottles is 12.000 ounces plus or minus 0.015 ounces, calculate the process capability index of the machine. Group of answer choices Less than or equal to 1 More than 4 More than 2 but less than or equal to 3 More than 1 but less than or equal to 2

the process capability index of the machine is 2.5

Option c) [More than 2 but less than or equal to 3] is the correct answer

Step-by-step explanation:

Given the data in the question;

process average ( x') = 12.000 ounces

standard deviation σ = 0.002 ounces

the design specification for the fill weight of the bottles is 12.000 ounces plus or minus 0.015 ounces.

so

Upper specification Limit USL = 12.000 + 0.015 = 12.015 ounces

Lower specification Limit LSL = 12.000 - 0.015 = 11.985 ounces

the process capability index of the machine will be;

Cp = ( process average - Lower specification Limit ) /  3σ

so we substitute

Cp = ( 12 - 11.985 ) / ( 3 × 0.002 )

Cp = 0.015 / 0.006

Cp = 2.5

Therefore, the process capability index of the machine is 2.5

Option c) [More than 2 but less than or equal to 3] is the correct answer

i think this could be a possible answer (1 / 84) -1

good luck! : d