A set of data contains 53 observations. The lowest value is 42 and the largest is 129. The data are to be organized into a frequency distribution. (a) How many classes would you suggest?
(b) What would you suggest as the lower limit of the first class? (Round your answer to the nearest whole number.)

53

Step-by-step explanation:

(a) Let, k is the number of classes and n is the number of observation.

So we select the class intervals such that for the smallest value of k, 2^k > n is satisfied.

Given, n = 53

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.