Suppose that Aces can be either high or low; that is, that {A, 2, 3, 4, 5} is a straight, and so is {10, Jack, Queen, King, Ace}. Moreover, a hand that is an Ace-high beats a King-high, etc. The number of ways of getting a five card hand that is a straight flush from a standard deck of cards is (Q) ?? The probability of being dealt a five card hand that is a straight flush from a well shuffled standard deck of cards is (Q) ??

If OR is exclusive in the question, meaning that Ace can either be high or low but not both would give you 36 possible combinations. However the question isn't exactly stated in a way that makes it easy to interpret this. Your logic is right though, and it could be an error on your sources part. The possible combos are

A 2 3 4 5

2 3 4 5 6

3 4 5 6 7

4 5 6 7 8

5 6 7 8 9

6 7 8 9 10

7 8 9 10 J

8 9 10 J Q

9 10 J Q K

10 J Q K A

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

answer is 12345678900987654321234567890987654321

step-by-step explanation: