Explain the connection between ∠2 and ∠B. A triangle has angle measures 50 degrees, 65 degrees, and B. 2 lines extend from a horizontal line to form 3 angles. The angles are 50 degrees, 2, 65 degrees.

∠2 ≅ ∠B

Step-by-step explanation:

Let the triangle be ABC,

Given that,

∠A = 50°

∠C = 65°

Using angle-sum property of the triangle,

∠A + ∠B + ∠C = 180°

50° + ∠B  + 65° = 180°

∵ ∠B = 65°         ...(i)

A.T.Q.

Two horizontal lines are extended making 3 angles. Two angles out of them are 50° and 65°.

Since the adjacent angles comprising a straight line is equals to 180°.

so,

∠2 + 50° + 65° = 180°

∠2 + 115° = 180°

∠2 = 180° - 115°

∵ ∠2 = 65°   ...(ii)

Using (i) and (ii),

∠2 ≅ ∠B

Therefore, ∠2 and ∠B are congruent to one another.

Sample Response: The sum of the measures of the interior angles of a triangle is 180°. m∠B + 50 + 65 = 180, so m∠B = 65°. The sum of adjacent angles forming a straight line is also 180°. m∠2 + 50 + 65 =180, so m∠2 = 65°. The angles are congruent.

Step-by-step explanation: its the sample response

2,600 divided by 80 = 32.5

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2