Two sailboats leave a harbor in the Bahamas at the same time. The first sails at 25 mph in a direction 340°. The second sails at 29 mph in a direction 210°. Assuming that both boats maintain speed and heading, after 5 hours, how far apart are the boats? A. 157.4 mi
B. 212 mi
C. 175 mi
D. 244.8 mi

9514 1404 393

  D. 244.8 mi

Step-by-step explanation:

The law of cosines can be used to find the distance between the boats.

The first boat will have traveled (5 h)×(25 mi/h) = 125 mi. The second boat will have traveled (5 h)×(29 mi/h) = 145 mi. The angle between their travel directions is 340° -210° = 130°.

  c² = a² +b² -2ab·cos(C) . . . . . for a=125, b=145, C=130°

  c² ≈ 59951.05

  c ≈ √59951.05 ≈ 244.8 . . . miles

The boats are about 244.8 miles apart after 5 hours.

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: