1.) Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution. 2.) Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.

3.) Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation

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Step-by-step explanation:

1. There will be no solution if the equation is a contradiction. Usually, it is something that can be reduced to 0 = 1.

If we choose to make our equation ...

  x = x +1

Subtracting x from both sides of the equation gives ...

  0 = 1

There is no value of the variable that will make this be true.

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2. Something that reduces to x = c will have one solution. One such equation is ...

  0 = x+1

  x = -1 . . . . subtract 1 from both sides

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3. Something that reduces to x = x will have an infinite number of solutions.

One such equation is ...

  x+1 = x+1

Subtracting 1 from both sides gives ...

  x = x . . . . true for all values of x

the answer is a if my teacher taught me correct

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.