A set of quiz scores has a mean of 78 and a standard deviation of 9. Using a common grading scale where 60 and above is a passing score, what percentage
of the students passed this test?
Explain your answer in terms of the 68-95-99.7 rule.

95%

Step-by-step explanation:

Given that :

Mean score, μ = 78 ; Standard deviation, σ = 9

To obtain the percentage of student that passed Given that, the average passing score is 60 and above, using the empirical rule :

Recall :

68% = Lies within 1 standard deviation of the mean

95% = Lies within 2 standard deviation of the mean

99.7% = Lies within 3 standard deviation of the mean

A score of 60 and above ;

Number of standard deviations

Z = (x - mean) / standard deviation

Z = (60 - 78) / 9 ;

Z = - 18/9

Z = - 2

Hence, this score lies within 2 standard deviations of the mean.

Hence, percentage of students who passed the test is 95%

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: