How many distinct permutations can be formed using the letters of the word robberies

mark me as brainliest plzz

this is the answer;No. of Permutations=3360.

Step-by-step explanation:

Suppose that, out of

n

things,

r

1

are of first type,

r

2

are of

second type,

r

3

are of third type,..., where

r

1

+

r

2

+

r

3

+

...

=

n

.

Then, no. of possible distinct permutations is given by

n

!

(

r

1

!

)

(

r

2

!

)

(

r

3

!

)

...

In our Example, there are total

8

letters in the word INFINITY ,

out of which,

3

letters are of one type (i.e., the letter I ),

2

are of second type (i.e., the letter N ) and the remaining

3

are

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: