The following house is called an A-frame house because it looks like the letter A from the front. Suppose that all edges of this A-frame house measure 6.5 yards, and the height of the house is 5.6 yards.

What is the area covered by the roof? [Type your answer as a number. Do not round.]

__ square yards

84.5 square yards roof

area of a square is A = a²

a = length of each side

The 2 triangular faces do not constitute "roof". The roof only covers 2 of the 3 square surfaces. Since we know the length of all edges is 6.5 yards:

A = (6.5)²

A = 42.25 yd²

This gives us the area of 1 of the 3 square sides. Since the roof covers 2 of the 3 sides (one is the floor/base), we must multiply times 2.

42.25 x 2 = 84.5

The height of the house would give you the area of the triangular faces, but since they are not considered "roof", you do not need to calculate their area.

4444444444444 i think