Consider a graph G that contains a vertex A. The vertex A is connected to 5 distinct vertices {V1, ..., V5}. Each of these vertices is connected to 4 vertices, all contained in {V6, ..., V25}. This construction continues with each of these vertices connected to 3 new, distinct vertices. These are each connected to 2 new, distinct vertices. And these are each connected to a new single distinct vertex (one new vertex for each vertex).

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

sine

step-by-step explanation: