The perimeter of a rectangle is 25 2/5 ft. The length is width. Find the length and width of the rectangle.

A. = 9.375 ft and w = 3.125 ft
B. = 9.525 ft and w = 3.175 ft
C. = 19.05 ft and w = 6.35 ft
D. = 7.85 ft and w = 4.85 ft

Width = 4.85 feet

Length = 7.85 feet

Step-by-step explanation:

Given:

Perimeter of a rectangle = 25 2/5 ft = 25.4 feet

Length = 3 + Width

Computation:

Assume;

Width = a

So,

Length = 3 + a

Perimeter of a rectangle = 2(l + b)

25.4 = 2[(3 + a) + a]

25.4 = 2[3 + 2a]

25.4 = 6 + 4a

4a = 19.4

a = 4.85

Width = 4.85 feet

Length = 3 + 4.85

Length = 7.85 feet

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

it’s the first one your welcome