Radius of circle is 6 and I need help finding the angles, SUT is 39 and MOP is 49 degrees

a. i) ∠TUV = 39°

ii) The measure of arc VTS (the minor arc) = 102°

b. The diameter OT of the circle = 12

c. The angle which we can calculate, given ∠MOP, is angle ∠OTM = 51°

i) Arc MVT = 98° and arc MO = 82°

Step-by-step explanation:

The given parameters are;

The radius of the circle = 6

∠SUT = 39°, ∠MOP = 49°

a. i) According to two tangent theory, two tangents that meet at a given point are congruent

Therefore, VU is congruent to SU

Given that PU is congruent to PU by reflexive property and PV = PS = The radius of the circle, we have;

ΔPVU is congruent to ΔPSU by Side Side Side (SSS) rule of congruency

∠SUT ≅ ∠TUV by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

Therefore, ∠SUT = ∠TUV = 39° by transitive property of equality

ii) Arc VTS is the minor arc while arc VOS is the major arc by size

The arc measure that describes arc VTS is the minor arc

iii) From circle theorem, we have that the sum of the angle formed by two tangents and the minor arc equals 180°

Therefore, ∠SUT + ∠TUV + arc VTS = 180°

∴ Arc VTS = 180° - (39° + 39°) = 102°

b. The line segment length that can be calculated based on knowing the radius length includes the length of the diameter OT of the circle

The diameter OT = 2 × The length of the radius

∴ The diameter OT = 2 × 6 = 12

c. The angle ∠MOP, is an interior angle of the right triangle ΔTMO formed by the diameter of the circle, OT, therefore, given that ∠MOP = 39°, we have;

∠OTM = 90° - ∠MOP

∴ ∠OTM = 90° - 39° = 51°

∠OTM = 51°

Therefore, given ∠MOP, we can calculate angle ∠OTM

i) The arc that we can calculate, given ∠MOP are arc MVT and arc MO

Arc MVT = 2 × ∠MOP

∴ Arc MVT = 2 × 49° = 98°

Arc MO = 2 × ∠OTM

∴ Arc MO = 2 × (90° - 49°) = 82°

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo