Find f′ in terms of g′ f(x)=x2g(x)

Select one:

f′(x)=2xf′(x)+2xg′(x)

f′(x)=2xg′(x)

f′(x)=2x+g′(x)

f′(x)=x2g(x)+2x2g′(x)

f′(x)=2xg(x)+x2g′(x)

9514 1404 393

  (e) f′(x)=2xg(x)+x²g′(x)

Step-by-step explanation:

The product rule applies.

  (uv)' = u'v +uv'

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Here, we have u=x² and v=g(x). Then u'=2x and v'=g'(x).

  f(x) = x²·g(x)

  f'(x) = 2x·g(x) +x²·g'(x)

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.

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step-by-step explanation: