Please Help Me With This Geometry Problem

Remember that the area of a square of sidelength L is:

A = L^2

And the area of a circle of diameter D is:

A = pi*(D/2)^2

If we inscribe a square in a circle, we will get four segments, like the ones shaded in the image below:

Notice that the diameter of the circle will be equal to the diagonal of the square.

And the diagonal of a square of side length L is:

d = √(2)*L

knowing that the side length of our square is 6 inches, the diameter of the circle will be:

D = √2*6in

Now, the total area of the four shaded parts will be equal to the difference between the area of the circle and the area of the square.

The area of the circle is:

A = pi*(√2*6in/2)^2 = (pi/2)*36in^2

The area of the square is:

A' = (6in)^2 = 36in^2

The difference is:

A - A' =  (pi/2)*36in^2 - 36in^2 = (pi/2 - 1)*36in^2

And there are 4 of these segments, then the area of every single one is one-fourth of that:

a = (1/4)*(pi/2 - 1)*36in^2 = (pi/2 - 1)*9 in^2

The area of each segment is:

a =  (pi/2 - 1)*9 in^2

if we replace pi by 3.14, the exact area will be:

a = (3.14/2 - 1)*9in^2 = 5.13 in^2

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: