Mathematics, 22.07.2021 04:30 coricori8

Cho hình chóp SABC có tam giác SAB cân tại A và nằm trong mặt phẳng vuông góc với mặt phẳng (ABC), tam giác ABC vuông tại B, AB = a, góc BAC = 60. Gọi H là trung điểm AB. Góc giữa SC và
mặt phẳng (ABC) bằng 60. Điểm M thuộc đoạn AC sao cho AC = 2AM. Tính thể tích khối chóp
S. BCMH và khoảng cách từ B đến (SAC)

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