A polynomial function has a root of -6 with multiplicity 1 a root of -2 with multiplicity 3 a root of 0 multiplicity 2 and a root a 4 with multiplicity 3 if the function has a positive leading pro fission and is of a odd degree which statement about the graph is true

the answer is b.)

< 1=< 2

hello umm i don't understand your question can you explain it more pls

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )