As part of their fundraising for Right To Play, the student council is having a fun-fair at lunch in the school yard. You will be running three events at different locations: a basketball foul-shot contest, a mini-putt course and a dunk-tank. Your job is to locate the ticket booth so that it will be the same distance from each of the events. Describe the process you would use to determine the position of the ticket booth.

Step-by-step explanation:

I used a co-ordinate graph and place the ticket booth at the origin then I chose difference of four but you can choose any and place three events equidistant from the origin by using the X- and Y- axis to easily determined a distance of 4 from the origin .

(0-4, 0) =( 4,0)

(0+4, 0) = (4 ,0)

(0, 0+4) = (0, 4)

if the both are placed first u would need to find the equation of a circle that contains all three points and place the booth at centre

you do this by creating the system of 3 equations inputting the x,y coordinates of each booth and solving for h,k,r

equation of a circle (X-H) 2 +( Y-K) 2 = r2

Hope It helps

:DD have a nice day

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )