a fair coin is flipped. if the flip results in a head, then a fruit is selected from a basket containing 8 apples, 2 bananas, and 6 cantaloups. if the flip results in a tail, then a fruit is selected from a basket containing 6 apples and 4 bananas. what is the probability that the flip resulted in tails, given that the fruit selexted is a banana g

Solution :

We have given two baskets :

: 8 apples + 2 bananas + 6 cantaloupes = 16 fruits

: 6 apples + 4 bananas = 10 fruits

A fair coin is made to flipped. If the results is head, then the fruit is selected from a basket .

If the flip results in tail, then the fruit is selected from the basket .

Probability of head P(H) =

Probability of tail P(T) =

if given event is :

B = selected fruit is BANANA

We have to calculate : P(T|B)

Probability of banana if the flip results is head P(B|H) =

Probability of banana if the flip results is tail P(B|T) =

From the Bayes' theorem :

Probability of flip results is tail when selected fruit is BANANA.

∴  

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )