Identify the segments that are parallel, if any, if ∠DCB,∠CBA are supplementary. A. DC¯¯¯¯¯¯¯¯ || AB¯¯¯¯¯¯¯¯
B. AD¯¯¯¯¯¯¯¯ || CB¯¯¯¯¯¯¯¯
C. AC¯¯¯¯¯¯¯¯ || CD¯¯¯¯¯¯¯¯
D. BA¯¯¯¯¯¯¯¯ || CA¯¯¯¯¯¯¯¯

Option A and Option B

Step-by-step explanation:

Properties of a parallelogram,

1). Opposite sides of a parallelogram are parallel and equal in measure.

2). Adjacent angles are supplementary.

Since, ∠DCB and ∠ACB are the supplementary angles,

ABCD will be a parallelogram.

Therefore, Opposite sides of the parallelogram ABCD will be parallel and equal in measure.

DC║AB and AD║CB

Option A and Option B are the correct options.

A

Step-by-step explanation:

i use same program

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18