What is the x-intercept of the graph of the function f(x) = x2 − 16x + 64? (−8, 0)
(0, 8)
(8, 0)
(0, −8)

(8,0)

Step-by-step explanation:

f(x) = x^2 − 16x + 64

The x intercepts ( or zeros) are found by setting y=0

0 =   x^2 − 16x + 64

Factor

0 = (x-8)(x-8)

Using the zero product property

x-8 =0  x-8 =0

x=8   x=8

(8,0)

answer: 1475

step-by-step explanation:

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