Match each equation with its number of unique solutions. y = 3x2-6x+3
y = -x2 - 4x + 7
y = -2x2+9x-11
Two Real Solutions
One Real Solution
One Complex Solution
Two Complex Solutionse de

y = 3x^2-6x+3    one real solution  

y = -x^2 - 4x + 7     two real solution

y = -2x^2+9x-11       two complex solutions

Step-by-step explanation:

b^2-4ac = 0   1 repeated real solution

b^2-4ac > 0   2 distinct real solutions

b^2-4ac < 0   2 complex solutions

step-by-step explanation:

except if the answer is in the value of money, then, it will matter. it will have to be $0.40, but i can tell this is not a money question, so .4 should be the right one.