Please Help!! To find the distance AB across a river, a distance BC of 786 m is laid off on one side of the river. It is found that B = 110.2° and C = 13.5°. Find AB. I don't understand how to do this but I know you need to use the Law of Sines, so please show work.

~ 220.6

Step-by-step explanation:

sine rule : a/sinA =b/sinB = c/sinC

AB/sinC =BC/sinA

A = 180 - 110.2 - 13.5 = 56.3 degrees

AB/sin13.5 = 786/sin56.3

AB = 786sin13.5/sin56.3 = 220.5506

the image of (6, 9) under a dilation is (4, 6). the scale factor is

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.