In a class ,30 offer biology ,21 offer chemistry and 22 offer physics. 15 offer physics and biology, 10 offer physics and chemistry and 13 offer biology and chemistry, 2 offer physics only,3offer chemistry only and 7 offer biology only. illustrate the information on a venn diagram. find the number of student who offer;offer all the three subjects, arein the class. If a student is selected at random what is the probability that, he studies either physics or chemistry.​

draw the Venn diagram. It is easy to fill in

2 offer Physics only,3 offer Chemistry only and 7 offer Biology only.

Now if we let

x = only Biology and Chemistry

y = only Biology and Physics

z = only Chemistry and physics

a = all three

Then we have

x+y+7+a = 30

x+z+3+a = 21

y+z+2+a = 22

There is no unique solution, since we do not know how many students there are in the class. But the above equations tell us that

y = x+2 = z+5

So some solutions are

x y z a Class

4 6 1 13 36

5 7 2 11 37

...

10 12 7 1 42

In a class,30 offer biology,21 offer are chemistry and 22 offer are physics.15 offer physics and biology,10 offer physics and chemistry and 13 offer biology and chemistry,2 offer physics only,5 offer chemistry only,and 7 offer biology only.(I)illustrate this information in a Venn diagram.(ii)find the number of students.(a)who offer all the three subjects.(b)in the class.(c)if a student s sellected at random what is the probability that is studies either physics or chemistry.

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it