Which ordered pairs make both inequalities true? Check all that apply. y < 5x + 2
y >= 1/2x + 1
These are the choices
#1. (–3, 2)
#2. (–1, 3)
#3. (0, 2)
#4. (1, 2)
#5. (2, –1)
#6. (2, 2)

If x = -2, then x 2-7x+10 equals a. 0 b.20 c.28

How is the equation of this circle written in standard form? x2 + y2 - 6x + 14y = 142 a) (x - 3)2 + (y + 7)2 = 200 b) (x+ 3)2 + (y - 7)2 = 200 (x - 6)2 + (y + 14)2 = 142 d) (x+6)2 + (y- 14)2 = 142

X/y + 4y/x divided by x/y - 2y/x explain as in depth as you can how you simplfied the fractions. i don't know where to start on this : /