On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3) crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3). Which statement is true about the graphed function?

F(x) < 0 over the interval (–∞, –4)
F(x) < 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –4)

f(x) > 0 over the interval  (–∞, –4)

Step-by-step explanation:

We know that:

Our curve has a minimum at (-2.5, -12)

Our curve has a maximum at (0, - 3)  (I assume that is a local maximum).

We know that the curve crosses the x-axes at (-4, 0)

We know that the curve crosses the y-axis at (0, -3)

Notice that when our curve crosses the x-axis at (-4, 0), it goes from above the axis to below the axis.

How we know this?

Remember that "crossing" the x-axis means that the sign of f(x) changes.

At the value x = -2.5  (which is larger than x = -4) the function is negative.

f(-2.5) = -12

and:

f(-4) = 0

So we can see that after f(x) crosses the x-axis at x = -4, the function is negative.

This means that before that point, the function must be positive.

So for values of x smaller than -4, the function should be larger than zero.

f(x) > 0 if x < -4

From this, we can conclude that in the range (-∞, –4), the function is above the x-axis.

Then we would write this as:

f(x) > 0 over the interval  (–∞, –4)

The correct option is the last option.

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.