Solving a Quadratic Equation When a ≠ 1 by Completing the Square Consider 8x2 - 48x = -104.

Write the equation so that

a = 1: x2 + _ x= _

Complete the square:

x2 – 6x + _ = –13 + _

Factor the trinomial and simplify:

(x +___ )² = _

Use the square root property of equality to solve
(x – 3)2 = –4.

The solutions are_

i got 10.28 but that rounds up to 10.3

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

brainliest

answer: it is 8

step-by-step explanation:

you know why its 8

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0