In a sports club of 150 members, 88 play golf, 63 play bowls, and 45 play golf and bowls. Find the probability that: a) a member plays golf only.
b) a member doesn't play golf or bowls.
pls explain too if u could. thanks!​

a) .287

b) .293

Step-by-step explanation:

The answers are boxed in red in the picture.

First I found how many people only golfed. Then I did the same for the people that only bowled. Next I found how many members didn't golf or bowl.

From there I found the probabilities by dividing

a.) # of members that only golf / total # of members

b.) # of members that don't bowl or golf / total # of members

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.