Find the symmetric difference between the following sets. (iii) X = {5, 6, 7} and Y={5, 7, 9, 10).​

X = {5, 6, 7}   ==>   X \ Y = {6}

(where X \ Y denotes the complement of X with respect to Y, i.e. elements belonging to X and not belonging to Y. Y contains both 5 and 7, so we remove these from X.)

Y = {5, 7, 9, 10}   ==>   Y \ X = {9, 10}

Then the symmetric difference is the union of these relative complements:

X ∆ Y = (X \ Y) U (Y \ X) = {6} U {9, 10} = {6, 9, 10}

muyb ajo

step-by-step explanation:

jegosu

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3