A postmix beverage machine is adjusted to release a certain amount of syrup into a chamber where it is mixed with carbonated water. A random sample of 25 beverages was found to have a mean syrup content of fluid ounces and the sample standard deviation is fluid ounces. Find a 95% two-sided confidence interval on the mean volume of syrup dispensed. Assume population is approximately normally distributed. Round your answers to 3 decimal places.

(1.1155 ; 1.1245)

Step-by-step explanation:

Given that :

Sample mean, xbar = 1.12

Sample standard deviation, s = 0.011

Sample size, n = 25

Since we are using the sample standard deviation, we use the T distribution ;

The confidence interval is defined as :

C. I = Xbar ± Tcritical * s/√(n)

Degree of freedom, df = n - 1 = 24

Tcritical(0.05, 24) = 2.064

C. I = 1.12 ± (2.064 * 0.011 / √25)

C.I = 1.12 ± 0.0045408

Lower boundary = (1.12 - 0.0045408) = 1.1155

Upper boundary = (1.12 + 0.0045408) = 1.1245

(1.1155 ; 1.1245)

the answer is c just got it on ed

step-by-step explanation: