Graph a triangle (STU) and reflect it over the y-axis to create triangle S′T′U′. Describe the transformation using words. Make sure you refer to the characteristics and the coordinates.
Draw a line segment from point S to the reflecting line, and then draw a line segment from point S′ to the reflecting line. What do you notice about the two line segments you drew? Do you think you would notice the same characteristics if you drew the line segment connecting T with the reflecting line and then T′ with the reflecting line? How do you know?

Solution given:

p(x,y)p'(-x,y)

By using the formula.

we can reflect it.

if a point (x,y) is reflected through y axis than it changes the direction of x but remains same of y.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°