Daniel used the formula to find the area of the following special trapezoid. His work is shown. Identify his error and correct it to find the area of the special trapezoid. \(\text{Line}\ 1:\ A=\frac{1}{2}\left(6\right)\left(7+ 7\right)\) \(\text{Line}\ 2:\ A=\frac{1}{2}\left(6\right)\left(14 \right)\) \(\text{Line}\ 3:\ A=\left(3\right)\left(7\right)\) \(\text{Line}\ 4:\ A=21\text{ cm}^2\)

Step-by-step explanation:

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I had the same issue.

Step-by-step explanation:

Here is the actual equation.

A=1/2(6)(7+7)

A=1/2(6)(14)

A=(3)(7)

A=21cm^2

He messed up on line 3 by multiplying 1/2 to both numbers. It should be A=(3)(14) and he would have gotten 42.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct