Find the shortest side of a triangle whose perimeter is 64, if the ratio of two of its sides is 4:3 and the third side is 20 less than the sum of the other two. A) 18
B) 20
C) 22
D) 24

i want to die

what the hell man, i just want the points lol

1 is c

2 is a

3 is a

step-by-step explanation:

hi there!

the answer will be d: 2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204