Suppose A is the sum of the first 50 consecutive multiples of 3, and B is the sum of the first 50 consecutive multiples of 6. What percent of A is B ? E. 50%
F. 75%
G. 100%
H. 200%

The correct answer is H. B is the 200% of A.

Since A is the sum of the first 50 multiples of 3, while B is the sum of the first 50 multiples of 6, to determine what percentage of A is B, the base numbers of both calculations must be considered, that is, 3 and 6. Thus, since 6 is 200% of 3 (6/3 = 2), B is 200% of A.

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the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)