Solve the equation for all values of x.
(22 – 16)(x2 + 49) = 0
Please help

-24.5 or 7i or -71 (see below)

Step-by-step explanation:

Im gonna guess that you mean (22-16)(2x+49)=0

Therefore, since one of the brackets must be equal to 0 and 22-16 is 6, 2x+49=0 so x is -24.5

However, if you meant (22-16)(x^2+49)=0

then x^2+49=0 so x^2 =-49

Therefore, the answer is complex and therefore 7i or -7i

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3