An observer, who is standing 47 m from a building, measures the angle of elevation of the top of the building as 30˚. If the observer’s eye is 167 cm from the ground, what is the exact height of the building?

9514 1404 393

  28.81 m

Step-by-step explanation:

The tangent relation can help find the height of the building above the observer's eye.

  Tan = Opposite/Adjacent

  Opposite = Adjacent·Tan

  above eye height = (47 m)(tan 30°) ≈ 27.14 m

Adding this to the eye height gives the height of the building above the ground where the observer is standing.

  27.14 m + 1.67 m = 28.81 m

The height of the building to the nearest centimeter is 28.81 meters.

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

75

step-by-step explanation: