Mathematics, 28.07.2021 18:20 milkshakegrande101

Identify the equation of the circle that has its center at (16, 30) and passes through the origin

Answers: 3

Show answers

Answers

To solve this question, we have to find the equation of the circle with given center and where it passes. Doing this, we get that the equation of the circle is:

(x - 16)^2 + (y - 30)^2 = 1156

Equation of a circle:

The equation of a circle with center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

Center at (16, 30)

This means that x_0 = 16, y_0 = 30

Thus

(x - 16)^2 + (y - 30)^2 = r^2

Passes through the origin:

We use this to find the radius squared, as this means that x = 0, y = 0 is part of the circle. Thus

(x - 16)^2 + (y - 30)^2 = r^2

(0 - 16)^2 + (0 - 30)^2 = r^2

r^2 = 16^2 + 30^2 = 1156

Thus, the equation of the circle is:

(x - 16)^2 + (y - 30)^2 = 1156

For another example to find the equation of a circle, you can look at

Answer from: Quest

maybe - definition of supplementary angles. im not sure. sorry

step-by-step explanation:

Answer from: Quest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer: (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

Another question on Mathematics

Mathematics, 22.06.2019 00:30

Round each of the decimals to the nearest hundredth a. 0.596 b. 4.245 c. 53.6843 d. 17.999

Answers: 2

Answer

Mathematics, 22.06.2019 02:00

Landon drove 103.5 miles on tuesday 320.75 miles on wednesday and 186.30 miles on thursday for work his company pays 0.07 $ for each mile he drives he expects to be paid more than $40,000 is he correct explain

Answers: 3

Answer

Mathematics, 22.06.2019 03:30

Find the sixth term of the following geometric sequence.

Answers: 1

Answer

Mathematics, 22.06.2019 04:20

Find a conversion factor between square centimeters and square meters. write it in three forms. square centimeters = 1 square meter

Answers: 1

Answer

You know the right answer?

Identify the equation of the circle that has its center at (16, 30) and passes through the origin...