Hal used the following procedure to find an estimate for StartRoot 82.5 EndRoot. Step 1: Since 9 squared = 81 and 10 squared = 100 and 81 < 82.5 < 100, StartRoot 82.5 EndRoot is between 9 and 10.

Step 2: Since 82.5 is closer to 81, square the tenths closer to 9.
9.0 squared = 81.00
9.1 squared = 82.81
9.2 squared = 84.64

Step 3: Since 81.00 < 82.5 < 82.81, square the hundredths closer to 9.1.
9.08 squared = 82.44
9.09 squared = 82.62

Step 4: Since 82.5 is closer to 82.62 than it is to 82.44, 9.09 is the best approximation for StartRoot 82.5 EndRoot.

In which step, if any, did Hal make an error?

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

w'x is 0.

hope it

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

i think the answer is d im not sure