The two dot plots below show the heights of some sixth graders and some seventh graders: The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 1.7. Approximately how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders

The number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4

Step-by-step explanation:

From the question, the mean absolute deviation (MAD) of the sixth graders = 1.2 and that of the seventh graders = 1.7

The variability in the heights of the sixth graders = 1.2

The variability in the heights of the seventh graders = 1.7

To calculate how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders, we will divide the variability of the seventh graders by the variability of the sixth graders

That is, 1.7/ 1.2 = 1.4167 ≅ 1.4

Hence, the number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet