Guided Practice You drop a handball from a height of 100 centimeters. Each curved path has 64% of the height of the previous path.

Write a rule for the sequence using centimeters. The initial height is when n = 1.

What height will the ball reach at the top of the sixth path?

A.
an=100 · (0.64)n−1a subscript n baseline equals 100 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; about 10.74 cm

B.
an=0.64 · (100)n−1a subscript n baseline equals 0.64 times left parenthesis 100 right parenthesis superscript n minus 1 baseline; about 0.11 cm

C.
an=1 · (0.64)n−1a subscript n baseline equals 1 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; 6,400,000,000 cm

A.

an=100 · (0.64)n−1a subscript n baseline equals 100 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; about 10.74 cm

Step-by-step explanation:  I got it off of the internet

Step 1 of 1

In geometric sequence, the ratio between two consecutive terms is constant. This ration is called the common ratio.

Consider the following sequence:

Thus the common ratio of the sequence is .

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You drop a handball from a height of 1 meter. Each curved path has 64% of the height of the previous path.   A. A(n)= 100*(0.64)^n-1

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b