is the perpendicular bisector of . Point T is the midpoint of . Point U lies on . If the length of is 7 units, the length of is how many units?

Complete question is;

RS is the perpendicular bisector of PQ . Point T is the midpoint of PQ. Point U lies on RS. If the length of UP is 7 units, the length of UQ is ______ units.

Triangle is attached

UQ = 7 Units

Step-by-step explanation:

From the image attached, we can see that;

T is the midpoint of PQ

Thus;

PT = TQ

Since RS is perpendicular to PQ, then we can say that;

∠PTU = ∠QTU

Now, from SAS congruence theorem, we can say that;

△PTU = △QTU

Thus, from corresponding sides of both triangles, we can say that;

UP = UQ

Thus,

UQ = 7 Units

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet