Find the equation whose roots are 3 and - 4​

y = x^2 + x - 12

Step-by-step explanation:

There are many possible equations that you could have however the simplest is a quadratic

if the roots are a and b then the quadratic will look like y=(x-a)(x-b)

so in this case y = (x-3)(x--4) = (x-3)(x+4)

expanding this gives y = x^2 + 4x - 3x - 12

y = x^2 + x - 12

Provided by Guathmaths

step-by-step explanation:

what grade level is this? need to know so i can look in my old textbooks!