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Mathematics, 30.07.2021 19:50 makaylahunt

Cho hình chóp S. ABCD có SA vuông góc với mặt phẳng (ABCD) và đáy ABCD là hình bình hành. Tam giác SAB có SA = 2a, SB = 5a. Khoảng cách từ điểm C đến mặt phẳng (SAB) bằng 3a. Tính thể tích của hình chóp SABCD

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Cho hình chóp S. ABCD có SA vuông góc với mặt phẳng (ABCD) và đáy ABCD là hình bình hành. Tam giác S...
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