May anyone help me with this please

x = - 8, x = - 4

Step-by-step explanation:

Given

x² + 15x + 30 = 3x - 2 ( subtract 3x - 2 from both sides )

x² + 12x + 32 = 0 ← in standard form

Consider the factors of the constant term (+ 32) which sum to give the coefficient of the x- term (+ 12)

The factors are + 8 and + 4 , since

8 × 4 = + 32 and 8 + 4 = + 12 , then

(x + 8)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x + 4 = 0 ⇒ x = - 4

can you put the picture up?

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)