A can do ajob in 16 days and B can do same job in 12 days. With the help of C they did the job in 4 days only. Then, C alone can do the job in..

48 days

Step-by-step explanation:

We know that,

Number of days A requires to do piece of work =16 days

Number of days B requires to do piece of work =12 days

Let us consider number of days C requires to do piece of work =x days

Number of days A,B and C together requires to do the piece of work =6 days

∴ We can calculate, work done by A in 1 day =1/16

Work done by B in 1 day =1/12

Work done by C in 1 day =1/x

Work done by A,B and C together in a 1 day =1/6

Now, work done by A,B and C together in 1 day is also equal to the sum of work done by each of them in 1 day =1/16+1/12+1/x=7/48+1/x

Therefore,

7/48+1/x=1/6

(7x+48)/48x=1/6

42x+288=48x

6x=288

x=288/6=48

∴C can do the work in 48 days.

answer:

c. the third graph