Jane has 200 feet of fencing to enclose a rectangular vegetable garden. One side of the garden will be alongside Jane's house so only three sides will need to be fenced. What is the largest area that can be enclosed by the 200 feet of fencing?

10,000 ft^2

Step-by-step explanation:

Let x represent length alongside Jane’s house and y represent width of garden.

We have been given that Jana has 200 feet of fencing to enclose a rectangular vegetable garden. One side of the garden will be alongside Jane’s house so only three sides will need to be fenced.

The fencing on 3 sides of garden will be equal to perimeter of garden on three sides.

p = x + 2y

200 = x + 2y

We know that area of rectangle is equal to length times width that is A = xy .

From perimeter equation, we will get:

x = 200 - 2y

Substituting this value in area equation, we will get:

A(y) = (200-y)y

Now, we need to find derivative of area of function.

A(y) = 200y - y^2

A'(y) = 200 - 2y

Now, we will set derivative equal to 0 to find critical points.

200 - 2y = 0

200 = 2y

y = 100

So thus the area will be maximum when 100.

A(y) = 200y - y^2

Substituting y for 100 we get A(100) = 10,000

10x

step-by-step explanation:

the greatest common factor 30 and 20 is 10

5 is a common factor of 30 and 20 but 10 is also a factor and 10 is greater than 5 so 5 will definitely not be apart of our answer

now the most amount of x's you factor our is just 1 factor of 1

so 10x the gcf of the terms in the polynomial

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.