3x - 2y = 16 and x - 2y = 4 (any method <3)​

If Im supposed to use the substituiton method, please notify me!

1) 3x-2y=16

Divide each term  by 3 and simplify

divide each term in 3x=16 +2y by 3

3x/3=16/3+2y/3

Cancel the common factor of 3

3x/3(cross this fraction out)=16/3+2y/3

divide x by 1

x=16/3+2y/3

2) x-2y=4

Solve for x

1) Add 2y to both sides.

Solve for y

1) Subtract x from both sides.

2) Divide both sides by -2.

step-by-step explanation:

most likely the answer is a.

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the answer is b.

step-by-step explanation: