Find the three consecutive 0dd integers such that two is less than 15 than 5 times the firs​

1

Step-by-step explanation:

1

Step-by-step explanation:

Find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first.

let the consecutive odd integers are :- x , x + 2 and x + 4.

According to question :-

the sum of the last two is 15 less than 5 times the first.

It means that

the sum of ( x + 2 ) and ( x + 4 ) is 15 less than 5 times the x .

( x + 2 ) + ( x + 4 ) = 5x - 15

x + 2 + x + 4 = 5x - 15

2x + 6 = 5x - 15

6 + 15 = 5x + 2x

21 = 7x

or ;

7x = 21

x = 21 / 7

x = 3

So, the consecutive odd numbers are :-

x = 3

x + 2 = 3 + 2 = 5

x + 4 = 3 + 4 = 7

=> 3 , 5 and 7

hope this helps you

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

ian gone lie this got me confused

step-by-step explanation: