Dave solved a quadratic equation. His work is shown below, with Step 111 missing. What could Dave have written as the result from Step 111? \begin{aligned} \dfrac{1}{3}(x+4)^2&=48 &&\text{Step }1 x+4&=\pm 12&\text{Step }2 x=-16&\text{ or }x=8&\text{Step }3 \end{aligned} 3 1 ​ (x+4) 2 x+4 x=−16 ​ =48 =±12 or x=8 ​ Step 1 Step 2 Step 3 ​ Dave solved a quadratic equation. His work is shown below, with Step 111 missing. What could Dave have written as the result from Step 111? \begin{aligned} \dfrac{1}{3}(x+4)^2&=48 &&\text{Step }1 x+4&=\pm 12&\text{Step }2 x=-16&\text{ or }x=8&\text{Step }3 \end{aligned} 3 1 ​ (x+4) 2 x+4 x=−16 ​ =48 =±12 or x=8 ​ Step 1 Step 2 Step 3 ​