PLZ HELP! I WILL PUT BRAINLIEST! Find the three digit numbers which have the the following properties: all three digits are different, the first digit is the square of the second digit and the third digit is one more than twice the second digit.

Step-by-step explanation:

1^2 = 1       This one is impossible. The digits have to be different.

2^2 = 4

3^2 = 9

so the first two digits can either be

4 and 2

9 and 3

The third clue is the one that decides. The third digit is odd and and 1 more than twice the second

The third digit can be 2 * 2 + 1 = 5 or 2*3 + 1 = 7. There is no way to choose between them.

So the answer is either 425 or 937. We cannot decide which. If there is another clue that will break the log jam, post it and I'll come back.

Step-by-step explanation:

1^2 = 1       This one is impossible. The digits have to be different.

2^2 = 4

3^2 = 9

so the first two digits can either be

4 and 2

9 and 3

The third clue is the one that decides. The third digit is odd and and 1 more than twice the second

The third digit can be 2 * 2 + 1 = 5 or 2*3 + 1 = 7. There is no way to choose between them.

So the answer is either 425 or 937. We cannot decide which. If there is another clue that will break the log jam, post it and I'll come back.