Solve for x if 25'+ 3(5') = 4​

x=0

Step-by-step explanation:

Let 5x = y.

(52)x+3(5x)−4=0

y2+3y−4=0

y2−y+4y−4=0

y(y−1)+4(y−1)=0

(y+4)(y−1)=0

y=−4;y=1

y = -4 is not possible.

y = 1 ⟹ x = 0.

43

step-by-step explanation:

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